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Which element has the ground state electron configuration [Ar]4s23d104p5? A) As B) Br C) Se D) Te

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Derrick

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Given electronic configuration is

[Ar]4s23d104p5

[Ar] is corresponds to Argon and it has 18 electrons. In 4S orbital, there are 2 electrons, 3d orbital there are 10 electrons and 4p orbital, there are 5 electrons.

Total number of electrons = 18+2+10+5 = 35.

We know that atomic number (Z) is the number of electrons or number of protons present in an atom.

Therefore atomic number of given element is 35.

It is corresponds to Bromine(Br)

Option-B is the correct answer.

Option-A: Arsenic (As) atomic number-33. Number of electrons are 33

Option-C: Selenium- Atomic number 34. Number of electrons are 34

Option D: Tellurium (Te): Atomic number 52. Number of electrons are 52

Option E: Iodine: Atomic number is 53. Number of electrons are 53.

Option B is the correct answer. 

 

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