Jan 2024 Update: Stratego: The object of the game is to capture the flag or capture/defeat all your opponent's pieces. Rank Piece No.

Question

Stratego: The object of the game is to capture the flag or capture/defeat all your opponent's pieces. Rank Piece No. per player Special properties B Bomb 6 Defeats any piece except Miner 1 Marshal 1 Can be defeated by the Spy N General 1 3 Colonel 2 4 Major 3 5 Captain 4. 6 Lieutenant 4 7 Sergeant 4 Miner 5 Can defuse bombs 8 9 Scout 8 S Spy 1 Can defeat the General or Marshal F Flag 1 Its capture ends the game Please create a Python program simulating a game of Stratego • Program must include Object/Class that creates the game pieces • Game will randomly generate 2 pieces (Player-1 vs. Player-2), winner of play determined by chart above (think the card game "War") • Although pieces are randomly generated, game should respect the odds/ratio of getting a particular piece • Game ends when one player captures the flag of their opponent

Asked By ShadowVoyager66 at 19 Jan 2024

Answered By Expert

Jaden

Expert · 5.4k answers · 5k people helped

$Pgnon\nSOL\nimpolt turtle\nimpolt math\nimport random\nwna turtle, screencs\nwn.bg color (black)\nwn. title (A Maze Games)\nwn. se$ $self gold - o\nAznos\ngo-up (selt):\n# calculate the spot to move to\nmove - to\nx self.xcore)\nmove to u self. y cores 1246\n#check$ $egno:\nb = self. Ycord-other. Ycore)\ndistance -\nmath.sart (la +*2)+(6+*2)\nit distance 25:\nreturn True\nelse:\nreturn false\nclass$ $Agno:\nself shape (lenemy - right gits\ndx=0\ndu - 24\nelit golf direction\ndown:\ndixo\ndy = 24\nelif self direction ==left:\ndx:$ $Panos\nif (move to move to y not in walls\npolo cmove tox, move to-4)\nI choose a different direction\nself, direction - random.c$ $Pg no :\n# Add maze to maze list\ntreasures append (Treasure (Screen , sereen y\nenemees.append (Enemy (screen_x, screen-4)\n& Ad$ $Pen & Pench\nPanor\nPlayer player\nI create wall coordinate ust\nwalls = []\nsetup-maze Klevels Li]) (H set up the lovel)\n# Key bo$ $Pgno: 8\nprint (Player dies!)\n# update screen\nwn.update (\n$

🧑‍🏫 More Questions

Lab Report: 14 Bacteriophage Specificity 1. What was the purpose of this exercise? 2. Complete the following table with your observations: Lysis (yes/no) Name of the bacterium S. Aureus (+) Yes Yes E. Coli (-) No Ent. Aerogenes (-) 3. How do you know if bacteriophage infected the bacteria? You can see a plaque. 4. Why didn't the bacteriophage infect all three bacteria? flest Cell specificity What is the explanation for bacteriophage specificity when it comes to infecting specific bacterium? wiceptors

Problem 4 - Starfish Starfish are known for being able to regenerate their bodies from a single leg if it is detached. Though we will not be harming any starfish, we will by counting hypothetically the number of starfish we can create by cutting a five legged starfish into five parts. For our problem, a starfish will regenerate one leg per "turn." Once it gets all five of its legs back, we will separate it into five legs which will then each start regenerating into five separate starfish. Our goal is to count the number of starfish after a specified number of generations or turns. For instance, if you start with a 2 legged starfish and a 5 legged one, then the next turn you will have a 3 legged starfish from a turn of regeneration and then five arms (one legged starfish) that we've separated. So the list will go from [2,5] to [3,1,1,1,1,1]. If you have multiple five legged starfish you must repeat the process for each of them. As another example, if you have a list containing [3,3,4,5,5] you will end up with [4,4,5,1,1,1,1,1,1,1,1,1,1] on the next turn. Given the number of generations and a starting list of starfish legs, write a function: def starfish(leg_list, generations): Sample Output Using the driver code here: def count_starfish(leg_list): leg_counts ={1:0,2:0,3:0,4:0,5:0} for x in leg_list: leg_counts [x]+=1 return leg_counts print (count_starfish (starfish ([1, 2, 3, 4, 5], 3))) print (count_starfish (starfish ([2,4,5],10))) print (count_starfish (starfish ([5,5,5],1))) print (count_starfish (starfish ([1], 20))) print (count_starfish (starfish ([5, 5, 5, 5, 5], 5))) linux5[109]8 python starfish.py {1:5,2:5,3:5,4:1,5:1} {1:0,2:25,3:0,4:25,5:25} {1:15,2:0,3:0,4:0,5:0} {1:625,2:0,3:0,4:0,5:0} {1:0,2:0,3:0,4:0,5:25}

1.) How might you add "Keystone species" to the concept map?  A.) Keystone species increase competition among all populations in a community.    B.) Keystone species are the most abundant members of communities. C.) Keystone species always live with other species in symbiosis. D.) Keystone species influence the diversity of communities.  2.) What is the correct relationship between the abiotic environment and trophic levels? (Select all that apply.) The resources available in the abiotic environment limit the number of trophic levels in a community. Fat soluble chemicals that organisms at low trophic levels obtain from the abiotic environment will decrease in concentration in the higher trophic levels. Organisms at the lowest trophic level of a community obtain nutrients directly from the abiotic environment. Some of the energy that producers obtain from the abiotic environment is lost at each trophic level.  3.) Herbivory has the same effect on species in a community as  competition. mutualism. commensalism. parasitism.

Which of the following statements is correct? Multiple Choice LIFO results in the same net income as FIFO when costs are rising. O FIFO results in a lower net income than LIFO when costs are rising. LIFO results in a higher net income than FIFO when costs are rising, C LIFO results in a higher net income than FIFO when costs are falling.

Question 2 (of 56) 2. Test your basic knowledge about clotting factors and anticoagulants. 1. Anticoagulants (Click to select) 2. Antithrombin (Click to select) 3. Heparin (Click to select) 4. Fibrinogen (Click to select) 5. Thrombin (Click to select) 6. Plasmin (Click to select) 7. Plasminogen (Click to select) 8. Streptokinase (Click to select) References eBook & Resources Multiple Choice Learning Objective: 18.04.05 Describe events in the common pathway. Sed esc F1 F2 F6

👉 Interested in exploring further?

Chrome Extension

1. Search answers from our 90+ million questions database.

2. Get instantly AI Solutions powered by most advanced models like GPT-4, Bard, Math GPT, etc.

3. Enjoy one-stop access to millions of textbook solutions.

4. Chat with 50+ AI study mates to get personalized course studies.

5. Ask your questions simply with texts or screenshots everywhere.

Get It

Compare

Legal