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Problem 4 - Starfish Starfish are known for being able to regenerate their bodies from a single leg if it is detached. Though we will not be harming any starfish, we will by counting hypothetically the number of starfish we can create by cutting a five legged starfish into five parts. For our problem, a starfish will regenerate one leg per "turn." Once it gets all five of its legs back, we will separate it into five legs which will then each start regenerating into five separate starfish. Our goal is to count the number of starfish after a specified number of generations or turns. For instance, if you start with a 2 legged starfish and a 5 legged one, then the next turn you will have a 3 legged starfish from a turn of regeneration and then five arms (one legged starfish) that we've separated. So the list will go from to . If you have multiple five legged starfish you must repeat the process for each of them. As another example, if you have a list containing you will end up with on the next turn. Given the number of generations and a starting list of starfish legs, write a function: def starfish(leg_list, generations): Sample Output Using the driver code here: def count_starfish(leg_list): leg_counts for in leg_list: leg_counts return leg_counts print (count_starfish (starfish ([1, 2, 3, 4, 5], 3))) print (count_starfish (starfish print (count_starfish (starfish print (count_starfish (starfish ([1], 20))) print (count_starfish (starfish ([5, 5, 5, 5, 5], 5))) linux5[109]8 python starfish.py

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Jasper

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Step 1/2

The working code for the starfish problem is as follows:

Explanation:

This function effectively simulates the regeneration and splitting process of starfish for the given number of generations and provides the leg count for each category of starfish.

Step 2/2

Explain the starfishing process step by step:

After it has processed all the constellations in the current generation, it uses a new_list to create a new leg_list. This prepares the next generation.

.

Final Answer

Once all generations are mapped, iterating through the final leg_list calculates the frequencies of starfish with 1, 2, 3, 4, and 5 legs . The list leg_count is used to keep track of the counts for each leg.

Finally, it returns the leg_count list, representing the number of stars with legs 1 through 5 after the specified number of generations.

Output :

{1: 5, 2: 5, 3: 5, 4: 1, 5: 1}

{1: 0, 2: 25, 3: 0, 4: 25, 5: 25}

{1: 15, 2: 0, 3: 0, 4: 0, 5: 0}

{1: 625, 2: 0, 3: 0, 4: 0, 5: 0}

{1: 0, 2: 0, 3: 0, 4: 0, 5: 25}

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