šŸŽBACK-TO-SCHOOL DEAL. Subscribe Now to get 40% OFF at only 8.49 USD/month, only valid until Sep 30th, 2024

Question

Question
What is the IUPAC name for the following compound?

Asked By WhisperingWaves87 at

Answered By Expert

Stanley

Expert Ā· 1.0k answers Ā· 1k people helped

Step 1/2

The following compound is given:

Here, the parent chain is alcohol. Count the number of carbon in the longest chain such that the alcohol group gets priority as shown below:

Explanation:

There are two functional group present in the given structure, that is, alkene and alcohol. From the priority order, alcohol will be given priority over alkene. Thus, numbering is done in such a way the alcohol group gets the least number.

Step 2/2

The max number of carbon in the chain is 8 with substituents present at the 5th and 6th positions.

There is another functional group present as well, that is, alkene at the 7th position.

Thus, the name of the compound is 5-ethyl-6-methyl-7-octen-4-ol.

Final Answer

Hence, the third option is correct. The name of the compound is as follows:

šŸ§‘ā€šŸ« More Questions

Problem 2 - Minor Key Here is a list of musical notes, written with flats (rather than sharps): CDb, D, Eb, E, F, Gb,G,Ab. ABb. B, C in the next octave) Observe that not all notes have flats, Le.Cflat is actually B which is not a black key on the piano for instance The harmonic minor scale is composed of the following sequence of steps: Step] [ Step) | Step) [Step] [13 Step] [1% Step] [ Step] For instance, the Charmonic minor scale is C, D, E, F, G, A.B.C. Each musical "half step" is a single step through the list, the name half-step predates computers so you have to forgive musicians a little. The Eb harmonic minor scale is Eb F Gb Ab Bb BDE The G harmonic minor scale is GABb CDE5 GbG Define a list: MUSICAL NOTES - ['c', D\u2660', 'D', 'E\0266d', TE", "Gu2663', 'G', A\u266d', 'A', '\u2660". Note that \u266d' is the unicode for the flat symbol Allow the user to enter starting notes like: "E* or "B flat" or "flat" You will have to calculate the starting note from this, or if it's not a note, for instance if they enter "R" Then display the harmonic minor scale starting at that note, or an error message indicating that it is not a note. When the user enters "quit then stop asking for notes and exit the program, My suggestion is that you break this problem down into parts: 1) Translate the input into the musical notation by creating a Thelper function' which takes as a parameter the user's input and outputs the proper note, meaning it will replace 'flat' with b and remove the space, so that it matches the description in the list of strings. 2) Compute the starting index in the list of musical notes or determine that the starting index doesn't exist because the note isn't a real note. I use another helper function for this purpose. 3) Calculate the scale itself in a slightly bigger function but then return it as a list. 4) Outside of your function, implement a main loop where you will join the answer together and output it. This is generally how programmers think about problems. We attempt to break each problem into subproblems which we can write small functions to solve. Then we put those functions together and get our final results. Sample Output linux5[109] python3 minor_key py Enter a starting note (D. E flat): G GAB CD EGG Enter a starting note (C, D flat): A ABCDETA A Enter a starting note (c, Dalat): A flat A B B D E EGA Enter a starting note (C, D flat): flat There is no starting note R. Enter a starting note (C, D flat): quit linux5[110]\ python3 minor_key.PY Enter a starting note (D, E flat): C CDEFGABC Enter a starting note (C, D flat): D DEFGAB DD Enter a starting note (C, D flat): E flat EFG A B BDE Enter a starting note c, flat): G GAB CD EGG Enter a starting note (C, D flat): flat DEEA ACD Enter at ting note (C, D flat): quit

and 2 Fill in the blanks: All tissues consist of two main components: , which consists of a gelatinous substance called numerous different and 3 An epithelial tissue that has one layer of rectangular cells would be classified as a stratified squamous epithelium. b. simple cuboidal epithelium. c stratified columnar epithelium d simple columnar epithelium 4 How do pseudostratified ciliated columnar epithelium and transitional epithelium differ from other types of epithelia? 5 True False: Mark the following statements concerning connective tissue proper and cartilage as true () or false 0). If the statement is false, correct it to make it a true statement Adipocytes contain a large lipid droplet in their cytoplasm. The primary element in dense regular collagenous connective tissue is ground substance. Bundles of collagen fibers are arranged parallel to one another in dense inregular colagenous connective tissue. Loose connective tissue contains all three protein fiber types Fibrocartilage has a smooth, glassy appearance due to a large amount of ground substance and few visible protein fibers 6 Which of the following best characterizes the extracellular matrix (ECM of bone tissue? a Bonetissue ECM consists of only calcium hydroxyapatite crystals b. Bone tissue ECM Consists of calcium hydroxyapatite crystals and collagen fibers c Bone tissue ECM consists of only colagen fibers. d. Bone tissue ECM consists of collagen, elastic, and reticular fibers. 7 Circle all that apply. Which of the following characteristics apply to skeletal muscle tissue a Striated b. Nonstrated C Multinucleate d Uninucleate e Contains intercalated discs. Voluntary 9 Involuntary h. Autorhythmic 128 - Exploring Anatomy & Physiology in the Laboratory

Problem 2 - Recursive Binary Create a recursive function in a file called binary.py: This recursive function should return the binaly representation of a number. Here is how to think about this problem. Writing a function that calculates the binary representation should always ask whether or not the number in question is even or odd. For instance, if you were to convert 5 into binary, 5 is odd so you know that the first digit should be a 1 . After this, then you should think about it this way, if you (integer) divide the number by 2 , then you'll get <span class="katex"><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:1em;vertical-align:-0.25em;"></span><span class="mord">5//2</span><span class="mspace" style="margin-right:0.2778em;"></span><span class="mrel">=</span><span class="mspace" style="margin-right:0.2778em;"></span></span><span class="base"><span class="strut" style="height:0.6444em;"></span><span class="mord">2</span></span></span></span>, and the binary for 2 is 10. If you put 10 together with 1 at the end, then you'll reach 101 which is the binary for 5 . How can you make this into a recursive process? When you think about the base case, you can use it to add the Ob to the binary number to match what the built in bin <span class="katex"><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:1em;vertical-align:-0.25em;"></span><span class="mopen">(</span><span class="mord mathnormal">x</span><span class="mclose">)</span></span></span></span> produces. When you use this driver code to call your function you should see that the binary expression matches. <span class="katex"><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.4306em;"></span><span class="mord mathrm">x</span><span class="mspace" style="margin-right:0.2778em;"></span><span class="mrel">=</span></span></span></span> int (input ('Tell me number: ')) while <span class="katex"><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.6944em;"></span><span class="mord mathrm">x</span><span class="mspace" style="margin-right:1em;"></span><span class="mclose">!</span><span class="mspace" style="margin-right:0.2778em;"></span><span class="mrel">=</span><span class="mspace" style="margin-right:0.2778em;"></span></span><span class="base"><span class="strut" style="height:0.7278em;vertical-align:-0.0833em;"></span><span class="mord">āˆ’</span><span class="mord">1</span></span></span></span> : print ('Ob' + binary (x), bin(x)) <span class="katex"><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.4306em;"></span><span class="mord mathrm">x</span><span class="mspace" style="margin-right:0.2778em;"></span><span class="mrel">=</span></span></span></span> int (input ('Tell me number: ')) linux5[109]\& python binary.py Tell me number: 5 Ob101 0b101 Tell me number: 21 Ob10101 0b10101 Tell me number: 57 Ob111001 Ob111001 Tell me number: 214 Ob11010110 Ob11010110 Tell me number: 12345 0b11000000111001 0b11000000111001 Tell me number: 3 Ob11 0b11 Tell me number: 2 Ob10 Ob10 Tell me number: 17 0b10001 0b10001 Tell me number: -1