Question
Asked By StormySeas69 at
Answered By Expert
Tim
Expert · 2.1k answers · 2k people helped
using minitab>stat>basic stat>one sample proportion
we have
Test and CI for One Proportion
Test of p = 0.999 vs p ≠ 0.999
Sample X N Sample p 95% CI Z-Value P-Value
1 100 104 0.961538 (0.924579, 0.998498) -12.09 0.000
a) the null hypothesis is
Ho:p=0.999
the alternative hypothesis is
Ho:p≠ 0.999
b ) two tailed test
c )sample proportion is 0.961538
d) test stat is -12.09
e ) Reject Ho
f)
est and CI for One Proportion
Test of p = 0.999 vs p < 0.999
Exact
Sample X N Sample p 95% Upper Bound P-Value
1 100 104 0.961538 0.986758 0.000
upper bound is 0.986758
g ) 99.9 % is implausible
🧑🏫 More Questions
👉 Interested in exploring further?
Chrome Extension
1. Search answers from our 90+ million questions database.
2. Get instantly AI Solutions powered by most advanced models like GPT-4, Bard, Math GPT, etc.
3. Enjoy one-stop access to millions of textbook solutions.
4. Chat with 50+ AI study mates to get personalized course studies.
5. Ask your questions simply with texts or screenshots everywhere.