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Step 1/2
The objective of the question is to determine the product of the reaction of a `"1-cyclopentylethanol"` with `PBr_{3},\ Mg` and `CH_{3}OH` .The substitution reactions are those in which a particular group in the compound gets replaced by a new group. If a nucleophile is the new group then the reaction is termed nucleophilic substitution.
Explanation:
A nucleophile can get substituted via two pathways, i.e., `S_{N}1` and `S_{N}2` . The former one involves a two-stepped mechanism whereas the latter one is a one-stepped reaction.Step 2/2
The reaction of a `"1-cyclopentylethanol"` with `PBr_{3},\ Mg` and `CH_{3}OH` is given as follows:Explanation:
In the reaction mechanism, The first step involves the nucleophilic attack of the `"O-atom"` of the `-OH` group on the electrophilic `"P-atom"` of ith `PBr_{3}` , one of ith `Br` is released as `Br^{-}` . Due to this, a positive charge is acquired by the `"O-atom"` . In the next step, the nucleophilic attack of `Br^{-}` occurs on the same `"C-atom"` containing `(OH^{+})PBr_{2}` group. This is an `S_{N}2` reaction, which produces `"1-bromoethyl cyclopentane"` and the removal of `(OH)PBr_{2}` is favored. The product formed then undergoes a reaction with `Mg` to form a Grignard reagent `"1-(cyclopentylethyl)magnesium bromide"` . The further reaction of this Grignard reagent with `CH_{3}OH` to give `"ethylcyclopentane"` and `CH_{3}O-MgBr` . It is an acid-base type of reaction in which `CH_{3}OH` is an acid that donates its `H^{+}` to the base (Grignard reagent) to synthesize an alkane.Final Answer
The correct option is `(c)` as the product formed is an alkane.🧑🏫 More Questions
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