Question
Asked By RadiantSkyline44 at
Answered By Expert
Wyatt
Expert · 5.4k answers · 5k people helped
Step 1/3
(a).
The object distance is,
`u=-24cm`Explanation:
As, in the question it is given that the object is located left side of the lens for that reason the object distance is taken as negative.
The focal length of the diverging lens is,
`f=-34.0cm`According to the lens formula,
`1/v-1/u = 1/f`
`1/v = 1/f+1/u`
`1/v = (u+f)/(uf)`
`v = (uf)/(u+f)`
`v = (-24*-34)/(-24-34)`
`v = -14.07cm`
So, the image will be formed at a distance `14.07cm` to the left side of the lens.Step 2/3
(b). The magnification is defined as,
`m = v/u`
`m = -14.07/-24`
`m = 0.59`
So, the magnification of the image is `m=0.59.`Explanation:
Here, the magnification has been calculated.
Step 3/3
(c).
In the ray diagram above `O` is the position of the object and `I` is the position of the image.Explanation:
Here, the ray diagram has been shown.
Final Answer
(a). The location of the image is `v=-14.07cm` .(b). The magnification of the image is `m=0.59`(c). The ray diagram has been shown in the above steps.
🧑🏫 More Questions
👉 Interested in exploring further?
Chrome Extension
1. Search answers from our 90+ million questions database.
2. Get instantly AI Solutions powered by most advanced models like GPT-4, Bard, Math GPT, etc.
3. Enjoy one-stop access to millions of textbook solutions.
4. Chat with 50+ AI study mates to get personalized course studies.
5. Ask your questions simply with texts or screenshots everywhere.