Feb 2024 Update: Perform the conversions between energy units. 8.70×102 kJ= It took 2632 J to raise the temperature of a sample of water from

Question

Perform the conversions between energy units.

8.70 \times 1 0^{2} kJ =

It took

2632 J

to raise the temperature of a sample of water from

16. 1^{\circ} C

36. 5^{\circ} C

. Convert 2632 J to calories.

Asked By CosmicDreams24 at 01 Feb 2024

Answered By Expert

Abel

Expert · 3.2k answers · 3k people helped

Step 1/2

To convert 8.70*10^2 kJ to J, we need to multiply the value by 1000 since there are 1000 J in a kJ:

`8.7010^2 kJ = 8.7010^2 * 1000 J = 8.70*10^5 J`

Therefore, 8.7010^2 kJ is equal to 8.70*10^5 J.

To convert 3255 Kcal to kJ, we need to multiply the value by 4.184 since there are 4.184 kJ in a Kcal:

`3255 Kcal = 3255 * 4.184 kJ = 13627.02 kJ `

Therefore, 3255 Kcal is equal to 1.362 × 10^4 kJ

To convert 5.27*10^6 J to kcal, we can use the conversion factor:

1 kcal = 4.184 kJ

First, we need to convert J to kJ by dividing 5.27*10^6 by 1000:

`5.27*10^6 J = 5.27*10^6 / 1000 kJ = 5270 kJ`

Then, we can convert kJ to kcal by dividing 5270 by 4.184:

5270 kJ/4.184 = 1,259.5602294455 kcal

Therefore, 5.27*10^6 J is approximately equal to 1.26 × 10^3 kcal.

Step 2/2

To convert 2632 J to calories, we need to divide the value by 4.184 since there are 4.184 J in a calorie:

`2632 J ÷ 4.184 = 629.1 cal`

In scientific notation 6.291 x 10^2

Final Answer

Ans1)

8.70 x 10^5 J

1.362 × 10^4 kJ

1.26 × 10^3 kcal.

Ans2)

6.291 x 10^2

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