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Alec
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Step 1/2
9.1
1. `5x^2=250`Divide each term in `5x^(2)=250` by `5` and simplify.`x^(2)=50`Take the specified root of both sides of the equation to eliminate the exponent on the left side.
`x=\pm \sqrt(50)`Simplify `\pm \sqrt(50)` .`x=\pm 5\sqrt(2)`The complete solution is the result of both the positive and negative portions of the solution.
`x=5\sqrt(2),-5\sqrt(2)`2. `3x^2+2=10`Move all terms not containing `x` to the right side of the equation.`3x^(2)=8`Divide each term in `3x^(2)=8` by `3` and simplify.`x^(2)=(8)/(3)`Take the specified root of both sides of the equation to eliminate the exponent on the left side.
`x=\pm \sqrt((8)/(3))`Simplify `\pm \sqrt((8)/(3))` .`x=\pm (2\sqrt(6))/(3)`The complete solution is the result of both the positive and negative portions of the solution.
`x=(2\sqrt(6))/(3),-(2\sqrt(6))/(3)`Step 2/2
3. `(x-2)^2=16`Take the specified root of both sides of the equation to eliminate the exponent on the left side.
`x-2=\pm \sqrt(16)`Simplify `\pm \sqrt(16)` .`x-2=\pm 4`The complete solution is the result of both the positive and negative portions of the solution.
`x=6,-2`4. `(5x+3)^2=45`Take the specified root of both sides of the equation to eliminate the exponent on the left side.
`5x+3=\pm \sqrt(45)`Simplify `\pm \sqrt(45)` .`5x+3=\pm 3\sqrt(5)`The complete solution is the result of both the positive and negative portions of the solution.
`x=(3\sqrt(5))/(5)-(3)/(5),-(3\sqrt(5))/(5)-(3)/(5)`5. `(2x+6)^2=20`Take the specified root of both sides of the equation to eliminate the exponent on the left side.
`2x+6=\pm \sqrt(20)`Simplify `\pm \sqrt(20)` .`2x+6=\pm 2\sqrt(5)`The complete solution is the result of both the positive and negative portions of the solution.
`x=\sqrt(5)-3,-\sqrt(5)-3`Explanation:
by solving quadratic equation.
Final Answer
Thus we get all answers
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