🎁BACK-TO-SCHOOL DEAL. Subscribe Now to get 40% OFF at only 8.49 USD/month, only valid until Sep 30th, 2024

Question

Question
An object is placed 14.0 cm from a diverging lens. A virtual image appears 10.0 cm from the lens on the same side as the object. Find the focal length of the lens. 14.0cm

Asked By SolarVoyager47 at

Answered By Expert

Andrew

Expert · 5.4k answers · 5k people helped

Step 1/2

Given data

`u = 14\ cm`

`v = 10\ cm`

Here, `u` is the object distance and `v` is the image distance.

Explanation:

Recall the expression of focal length of the lens to find the solution of the problem,

Step 2/2

The focal length of the lens can be obtained as

`1/f = 1/u+1/v`

Substitute the known values

`-1/f = 1/14+1/10`

`-1/f = 24/140`

`f = -140/24`

` \cong -5.84\ cm`

Explanation:

The focal length for the diverging lens is negative.

Final Answer

The focal lenth of the lens is `-5.84\ cm.`

🧑‍🏫 More Questions

Name Section Experiment 10 Advance Study Assignment: Analysis of an Aluminum-Zinc Alloy 1. On the following page, construct a graph of No, vs. % Al. To do this, refer to Equation 11 and the discus- sion preceding it. Note that a plot of N vs. % Al should be a straight line (why?). To fix the position of a straight line, it is necessary to locate only two points. The most obvious way to do this is to find No, when % Al = 0 and when % A1 = 100. If you wish you may calculate some intermediate points (for example, Nu, when % Al = 50, or 20, or 70); all these points should lie on the same straight line. To use a spread- sheet, set up Equation 11 for different Al percentages. Graph Nyt, vs. % Al. 2. A student obtained the following data in this experiment. Fill in the blanks in the data and make the indicated calculations: Mass of gelatin capsule 0.1134 g 23°C Ambient temperature, 23+273=296 Mass of capsule plus alloy sample 0.3218 g Ambient temperature, T 296 K Mass of alloy sample, m g Atmospheric pressure 732 mm Hg Vapor pressure of H20 at 1 (Appendix I) Mass of empty beaker 154.3 g mm Hg Mass of beaker plus displaced water 401.6 g Mass of displaced water Pressure of dry H2 g PH, (Eq. 7) mm Hg Volume of displaced water (density = 1.00 g/mL) atm mL Pressure of dry HZ L Volume, V, of H2 = Volume of displaced water mL = Find the number of moles of H, evolved, nu, (Eq. 5; V in liters, Pit in atm, T in K, R= 0.0821 liter- atm/mole K). moles H2 Find, NH, the number of moles of H, per gram of sample (Mu,m). moles H/g Find the % Al in the sample from the graph prepared for Problem 1. % Al Find the % Al in the sample by using Equation 11. % A006C Advance Study Assignment: Analysis of an Aluminum-Zinc Alloy 0.050 0.040 0.030 VHA 0.020 0.010 25% 50% 75% 100% % AI (11) 100-%A1 -X0.0153 + 100 in Nu = (100X0.0556) We can solve Equation 11 directly for % Al if we know the number of moles of H, evolved per gram of sample. To save time in the laboratory and to avoid arithmetic errors, it is highly desirable to prepare % Al in the sample can be read directly from the graph. Directions for preparing such a graph are given in advance a graph giving Nh, as a function of % Al. Then when Nh, has been determined in the experiment, Problem 1 in the Advance Study Assignment.