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REPORT SHEET EXPERIMENT Abbreviated 32 Qualitative Analysis Scheme PART I: GROUP 1 CATIONS Record the reagent used in each step, your observations, and the equations for each precipitation reaction. Mark (+) f observed in unknown Procedure Reagent Observations G1-1 Precip G1-2 hia Dar ou Cations in group 1 unknown

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Step 1/3

Write the equations for the following observations:

The group `1` cations are : `Ag+ , Pb^2+ , and Hg2^2+`

Equations:

`Ag+ + HCl -> AgCl_{(s)} + H+``Pb^2+ + HCl -> PbCl2_{(s)} + H+``Hg2^2+ + HCl -> Hg2Cl2_{(s)}+ H+`

Explanation:

The heavy metal ions precipitate as their respective chlorides. The metal chloride precipitates are white in color.

Step 2/3

`Pb^2+ + K2CrO4 -> PbCrO4 + 2K^+`

Explanation:

When lead ions react with potassium chromate, yellow coloured precipitate of lead chromate is formed.

Step 3/3

`Hg2Cl2_{(s)} + 2NH3_{(aq)}⟶Hg_{(l)} + HgNH2Cl_{(s)} + NH^4+_{(aq)} + Cl−_{(aq)}`

Explanation:

When mercury( `I` ) chloride and ammonia combine, a combination of white `HgNH2Cl ` (s) and black `Hg` (l) is produced that looks to be a gray solid. The existence of this gray solid indicates that `Hg2^2+` is present.

Final Answer

The equations are as follows:

`Ag+ + HCl -> AgCl_{(s)} + H+``Pb^2+ + HCl -> PbCl2_{(s)} + H+``Hg2^2+ + HCl -> Hg2Cl2_{(s)}+ H+``Pb^2+ + K2CrO4 -> PbCrO4 + 2K^+``Hg2Cl2_{(s)} + 2NH3_{(aq)}⟶Hg_{(l)} + HgNH2Cl_{(s)} + NH^4+_{(aq)} + Cl−_{(aq)}`

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