Question
Asked By CosmicGlider20 at
Answered By Expert
Felix
Expert · 4.3k answers · 4k people helped
Solution By Steps
Step 1: Differentiate each term
To find
\frac{d y}{d x}, we need to differentiate
y = e^{\sqrt{x}} + e^{-\sqrt{x}} with respect to
x.
Step 2: Apply the chain rule
For
e^{\sqrt{x}}, let
u = \sqrt{x}, then
\frac{d}{dx} e^{\sqrt{x}} = e^{\sqrt{x}} \cdot \frac{d}{dx} \sqrt{x} = e^{\sqrt{x}} \cdot \frac{1}{2\sqrt{x}}.
For
e^{-\sqrt{x}}, let
u = -\sqrt{x}, then
\frac{d}{dx} e^{-\sqrt{x}} = e^{-\sqrt{x}} \cdot \frac{d}{dx} (-\sqrt{x}) = e^{-\sqrt{x}} \cdot \left(-\frac{1}{2\sqrt{x}}\right).
Step 3: Combine the results
Combining the derivatives, we get:
\frac{d y}{d x} = \frac{e^{\sqrt{x}}}{2\sqrt{x}} - \frac{e^{-\sqrt{x}}}{2\sqrt{x}} = \frac{e^{\sqrt{x}} - e^{-\sqrt{x}}}{2\sqrt{x}}
Final Answer
The derivative of
y = e^{\sqrt{x}} + e^{-\sqrt{x}} with respect to
x is:
\boxed{A}
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