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Question

Question
Part A A solution is saturated in N_(2) gas and KCl at room temperature. What happens if the solution is warmed to 75°C ? Gasoous N_(2) bubbles out of solution. Solid KCl precipitates out of solution. Nothing happens (both N_(2) and KCl remain in solution). Solid KCl precipitates out of solution and gaseous N_(2) bubbles out of solution.

Asked By LightningWhisper25 at

Answered By Expert

Mickey

Expert · 4.3k answers · 4k people helped

Answer

Solid KCl precipitates out of solution and gaseous N_{2} bubbles out of solution.

Explanation

When a solution is saturated with nitrogen gas (N_{2}) and potassium chloride (KCl) at room temperature, and then warmed to 75°C, the solubility of the gases in water decreases with increasing temperature. This means that the N_{2} gas will become less soluble and will tend to bubble out of the solution. On the other hand, the solubility of solids like KCl generally increases with temperature. However, if the solution was already saturated with KCl at room temperature, it is possible that the solution could become oversaturated with KCl at higher temperatures, leading to the precipitation of solid KCl. Therefore, both the N_{2} gas will bubble out, and solid KCl may precipitate out of the solution.