Question
Asked By CrimsonShadow33 at
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Jared
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Answer
The calculation would be;108g HCl ------- 100g waterxg HCl ------- 50g of waterNow, by multiplying cross pairs;108g * 50g = x * 100gRearranging for x, we get;x = 108g * 50g / 100g = 54gTherefore, 54 grams of HCl can be dissolved in 50g of water at 50°C.
Explanation
This question is related to the solubility of HCl in water at a specific temperature. Before we continue, we must have the solubility chart for HCl. The solubility of HCl at different temperatures will help us determine the maximum amount that can be dissolved in 50g of water at 50°C. The solubility of HCl at different temperatures is as follows:- At 0°C, the solubility is 79g/100g water- At 20°C, the solubility is 88g/100g water- At 40°C, the solubility is 97g/100g water- At 60°C, the solubility is 108g/100g water- At 80°C, the solubility is 119g/100g water- At 100°C, the solubility is 130g/100g waterFrom the chart, we can see that the solubility of HCl in 100g of water is 108g at 60°C. Therefore, to calculate the amount of HCl in 50g of water at 50°C, we apply a simple proportion calculation.
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