Question
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Asked By DreamWeaver94 at
Answered By Expert
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Roger
Expert · 3.2k answers · 3k people helped
Step 1/1
According to the percentage ionic character formula:
% ionic character `= [16 x ΔEN + 3.5 x (ΔEN)^2]`
Explanation:
Where, ΔEN = electronegativity change
In Boron phosphite, `ΔEN = 2.1 - 2.0 = 0.1`
Therefore,
%ionic character `= 16 * 0.1 + 3.5 * (0.1)^2`
`= 1.60 + 0.035= 1.635`
Fraction of ionic bond `=1.635 / 100 = 0.01635 = 0.0164`
Final Answer
Rounded to three decimal places, it is 0.0164.
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