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The compound boron phosphide (BP) is a compound semiconductor having mixed ionic and covalent bonding. The electronegativities for B and P are 2.0 and 2.1 respectively. Calculate the fraction of the bonding that is ionic. (Enter your answer to three significant figures.) ionic

Asked By DreamWeaver94 at

Answered By Expert

Roger

Expert · 3.2k answers · 3k people helped

Step 1/1

According to the percentage ionic character formula:

% ionic character `= [16 x ΔEN + 3.5 x (ΔEN)^2]`

Explanation:

Where, ΔEN = electronegativity change

In Boron phosphite, `ΔEN = 2.1 - 2.0 = 0.1`

Therefore,

%ionic character `= 16 * 0.1 + 3.5 * (0.1)^2`

`= 1.60 + 0.035= 1.635`

Fraction of ionic bond `=1.635 / 100 = 0.01635 = 0.0164`

Final Answer

Rounded to three decimal places, it is 0.0164.

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