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The formula for dinitrogen tetrafluoride is N2F4. a. How many grams of nitrogen are present in 1.54 moles of dinitrogen tetrafluoride? grams b. How many moles of fluorine are present in 2.19 grams of dinitrogen tetrafluoride? moles The formula for disulfur decafluoride is S2F10- a. How many grams of sulfur are present in 1.93 moles of disulfur decafluoride 2 grams b. How many moles of fluorine are present in 2.23 grams of disulfur decafluoride? moles

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Step 1/2

In this question, given that the formula of dinitrogen tetrafluoride `(N_2F_4)`

Given that,

`\text{Number of moles of N}_2F_4=1.54\text{ mol}`

We have to calculate the amount of nitrogen in grams.

Explanation:

The number of moles is a fundamental concept in chemistry, used to measure the quantity of substance. One mole of any substance contains Avogadro's number of entities, which is approximately `6.022*10^23` particles.

Step 2/2

The amount of nitrogen can be calculated using the equation,

`\text{Amount of nitrogen} = \frac{mass}{molar mass}`

`\text{ molar mass of N}_2F_4 = 104.02\text{ g/mol}`

`\text{Mass of N}_2 = 2*14\text{ g/mol}`

`\text{Amount of nitrogen} = \frac{2*14\text{ g/mol}}{104.02\text{ g/mol}`

` = 0.4144\text{ mol}`

One mole of `N_2F_4` contains ` 0.2691\text{ moles}` , so `1.54\text{ mole}` contains,

`\text{Amount of nitrogen = 0.2691\text{ moles}*1.54\text{ mol}`

` = 0.4144\text{ mol}`

`\text{Mass of nitrogen} = \text{ moles}*\text{ Molar mass of nitrogen} `

`\text{ Molar mass of nitrogen} = 14\text{ g/mol}`

` \text{Mass of nitrogen} = 0.4144\text{ mol}*14\text{ g/mol} `

` = 5.8\text{ g} `

2)In the second question,

`\text{Mass of N}_2F_4=2.19\text{ g}`

We have to calculate the number of moles of fluorine.

The number of moles can be calculated by the formula,

`\text{moles} = \frac{mass}{molar mass}`

`\text{ molar mass of N}_2F_4 = 104.02\text{ g/mol}`

`\text{Number of moles of N}_2F_4 = \frac{2.19\text{ g}}{104.02\text{ g/mol}`

` = 0.02105\text{ mol}`

One mole of `N_2F_4` has `4 \text{ mol}` of fluorine.

So,

`\text{Number of moles of F} = 4*0.02105\text{ mol}`

` = 0.0842\text{ mol}`

Explanation:

To find the amount of substance in grams, we can multiply the number of \text{ mol} by the bolar mass. The number of moles is the quantity of substance in `\text{ mol}.` The molar mass is expressed in `\text{ g/mol}.`

Final Answer

1)Amount of nitrogen is, `5.8\text{ g} ` 2) moles of fluorine is, `0.0842\text{ mol}`

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